@pony If only ![]()
@Merlin Definitely thank you for the info
@animeirl I don't either so please don't fall for sensationalism.
@animeirl Any evidence beyond click bait headlines, OOC sound bites and poor reading comprehension.
@animeirl that's the objective description
@animeirl by outed as pedo you mean quote mined by commies
@animeirl He's running a thriving media company. And thanks to Musk he got unbanned from Twitter now.
@johnbudd1350 Thanks, but how to do it when a range in array2 starts at 0 or ends at end of array1?
If it doesn't you first need to call the function before looping through array2, but you don't know where to end before looping through array2.
I think I might need to make a new array with the acceptable ranges and just loop through that.
@johnbudd1350 Yeah
@Corfiot @johnbudd1350 I can create anything I want. Just can't touch the arrays.
@johnbudd1350 I'm not given a list of ranges. I only know length of array1.
@johnbudd1350 I want to call the function (the function has 3 arguments, start and end index, and array1) on black parts individually, but the start and end of the red parts is in a different array.
I'm the joke, but you're the punchline.
I run this website. I like posting funnies and fugging lolis.